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## 1.) what are the two integers whose sum is -20

**Ask: **1.) what are the two integers whose sum is -20 and whose difference is 14?

2.) what are the two integers whose sum is -23 and whose difference is 37?

3.) what are the two integers whose sum is 13 and whose difference is 23?

4.) what are the two integers whose sum is -7 and whose difference is 25?

5.) what are the two integers whose sum is -25 and whose difference is 11?

__The number of possible integer pairs is 15*14__

__The number of possible integer pairs is 15*14__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 – (91/285)=194/285 ~ 0.6807.__

__The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 – (91/285)=194/285 ~ 0.6807.__

__The number of possible integer pairs is 15*14__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619__

__The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.__

__The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.__

__The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 – (91/285)=194/285 ~ 0.6807.__

__HOPE____ ____IT____ ____HELP____ ____U____🙂 __

## Estimate the volume of a rectangular prism whose length is

**Ask: **Estimate the volume of a rectangular prism whose length is 19.8cm whose width is 5.9 cm and whose height is 9.7cm

**Answer:**

the answer is **1****1****3****3****.****1****5****4**** **

**hope ****my ****answer ****is ****correctly**

**[tex]largecolor{pink}{rm{colorbox{purple}{Raburikyatto : Quatro : Squad}}}[/tex]**

## whose sum is -25 and whose difference is 11

**Ask: **whose sum is -25 and whose difference is 11

**Answer:**

Find two numbers whose sum is 11 and whose difference between their … We are given these two equalities x + y = 11, (1) x^2 – y^2 = 33.

**Step-by-step explanation:**

## what is the area of a circle whose radius is

**Ask: **what is the area of a circle whose radius is 6 cm?

what is the area of a triangle whose height is 0.16 m and whose base is 0.9 m?

what is the area of a parallelogram whose base is 14cm and whose height is 16cm?

**Answer:**

1. 36π cm2.

2. 0.072m²

3. A=224cm²

#CARRYONLEARNING

## find the sum of a geometric series whose A1 =

**Ask: **find the sum of a geometric series whose A1 = 3 whose An = 786 , 432 and whose common ratio is 4

the formula for An=a1(r^n-1)

An=786,432

is in the 10th term of G.P

by getting the sum of it. this is the formula:

S=a1(r^n – 1)/r-1

substitute:

S=1048575…That’s the answer..

## A cylinder whose height is 44cm and whose radius is

**Ask: **

A cylinder whose height is 44cm and whose radius is 11cm

## CYLINDER

[tex]__________________________[/tex]

Note: Since there are no instructions, I will solve for both surface area and volume

### GIVEN

- Height = 44 cm
- Radius = 11 cm

### SURFACE AREA

[tex]sf large SA = 2 pi r : (r + h)[/tex]

[tex]sf large SA = 2 times 3.14 times 11 :: (11 + 44)[/tex]

[tex]sf large boxed{ sf SA = 3799.4 : cm^2}[/tex]

### VOLUME

[tex]sf large V = pi r ^2h[/tex]

[tex]sf large V = 3.14 times 11 ^{2} times 44[/tex]

[tex]sf large boxed {sf V = 16717.36 cm^3}[/tex]

## E: A number whose absolute value is 0A: A negative

**Ask: **E: A number whose absolute value is 0

A: A negative number whose absolute value is 6

D: A positive number whose absolute value is 7

G: A positive number whose absolute value is 3

I: A negative number whose absolute value is 4

0: A positive number whose absolute value is 5

P: A negative number whose absolute value is 10

R: A negative number whose absolute value is 8

S: A negative number whose absolute value is 2

**Answer:**

**E****.**** ****0**

**A****.**** ****–****6**

**D****.**** ****7**

**G****.**** ****3**

**I****.**** ****–****4**

**O****.**** ****5**

**P****.**** ****–****1****0**

**R****.**** ****–****8**

**S****.**** ****–****2**

**Remember****:**** ****The**** ****absolute**** ****value**** ****of**** ****a**** ****number**** ****means**** ****the**** ****distance**** ****from**** ****zero****.**

**Step-by-step explanation:**

hope it helps po. pwede po paki-brainliest. need lang po for the next rank. thank you po❤️

## Find two integers1.) Whose sum is 13 and whose difference

**Ask: **Find two integers

1.) Whose sum is 13 and whose difference is 23.

2.) Whose sum is -7 and whose difference is 25.

3.) Whose sum is -23 and whose difference is 37.

**Answer:**

1.36

2.14,625

3.26,851

**Step-by-step explanation:**

Sana makatulong ito sa iyong pag-aaral❤

## whose are the people whose work are related to environmental

**Ask: **whose are the people whose work are related to environmental health

DENR

**Explanation:**

Environmental Toxicologist

Air Pollution Analyst

## Pa help itong tatlo nalang hindi ko pa nasasagutan.Find two

**Ask: **Pa help itong tatlo nalang hindi ko pa nasasagutan.

Find two integers

1.) Whose sum is 13 and whose difference is 23.

2.) Whose sum is -7 and whose difference is 25.

3.) Whose sum is -23 and whose difference is 37.

**Answer:**

1.16,299

2.14,350

3.46,1702

**Step-by-step explanation:**

Sana makatulong ito sa iyo

Hope it help

Not only you can get the answer of **whose**, you could also find the answers of E: A number, Estimate the volume, find the sum, whose are the, and whose sum is.