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1.) what are the two integers whose sum is -20
Ask: 1.) what are the two integers whose sum is -20 and whose difference is 14?
2.) what are the two integers whose sum is -23 and whose difference is 37?
3.) what are the two integers whose sum is 13 and whose difference is 23?
4.) what are the two integers whose sum is -7 and whose difference is 25?
5.) what are the two integers whose sum is -25 and whose difference is 11?
The number of possible integer pairs is 15*14
The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10
The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619
The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.
The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.
The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 – (91/285)=194/285 ~ 0.6807.
The number of possible integer pairs is 15*14
The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10
The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619
The number of possible integer pairs is 15*14The pairs that sum to 20 are (5,15), (6,14),…, (15,5) except for (10, 10): (15-5+1)–1=10The probability is P=10/210=1/21 ≈ 0.047619The sample space of all possible choices of three integers from the set {1,2,…..,20} has C(20,3) = (20×19×18)/3! elements.
The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.
The complement of the event space E consists of all possible choices of three integers from the complement of the set of all the multiples of 3 in the above set because the product of the chosen integers is a multiple of 3 if and only if at least one of them is a multiple of 3. Hence we have to choose three elements from the set {1,2,4,5,7,8,10,11,13,14,16,17,19,20} which has 14 elements. Hence |E’| = C(14,3) = 14×13×12/3!. Therefore probability P(E’) = |E’|/|S| = (14×13×12)/(20×19×18)= (14×13×2)/(20×19×3) =(7×13)/(5×19×3) = 91/285.Therefore the required probability of the product of the chosen integers being a multiple of 3 is P(E)= 1 – (91/285)=194/285 ~ 0.6807.
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Estimate the volume of a rectangular prism whose length is
Ask: Estimate the volume of a rectangular prism whose length is 19.8cm whose width is 5.9 cm and whose height is 9.7cm
Answer:
the answer is 1133.154
hope my answer is correctly
[tex]largecolor{pink}{rm{colorbox{purple}{Raburikyatto : Quatro : Squad}}}[/tex]
whose sum is -25 and whose difference is 11
Ask: whose sum is -25 and whose difference is 11
Answer:
Find two numbers whose sum is 11 and whose difference between their … We are given these two equalities x + y = 11, (1) x^2 – y^2 = 33.
Step-by-step explanation:
what is the area of a circle whose radius is
Ask: what is the area of a circle whose radius is 6 cm?
what is the area of a triangle whose height is 0.16 m and whose base is 0.9 m?
what is the area of a parallelogram whose base is 14cm and whose height is 16cm?
Answer:
1. 36π cm2.
2. 0.072m²
3. A=224cm²
#CARRYONLEARNING
find the sum of a geometric series whose A1 =
Ask: find the sum of a geometric series whose A1 = 3 whose An = 786 , 432 and whose common ratio is 4
the formula for An=a1(r^n-1)
An=786,432
is in the 10th term of G.P
by getting the sum of it. this is the formula:
S=a1(r^n – 1)/r-1
substitute:
S=1048575…That’s the answer..
A cylinder whose height is 44cm and whose radius is
Ask:
A cylinder whose height is 44cm and whose radius is 11cm
CYLINDER
[tex]__________________________[/tex]
Note: Since there are no instructions, I will solve for both surface area and volume
GIVEN
- Height = 44 cm
- Radius = 11 cm
SURFACE AREA
[tex]sf large SA = 2 pi r : (r + h)[/tex]
[tex]sf large SA = 2 times 3.14 times 11 :: (11 + 44)[/tex]
[tex]sf large boxed{ sf SA = 3799.4 : cm^2}[/tex]
VOLUME
[tex]sf large V = pi r ^2h[/tex]
[tex]sf large V = 3.14 times 11 ^{2} times 44[/tex]
[tex]sf large boxed {sf V = 16717.36 cm^3}[/tex]
E: A number whose absolute value is 0A: A negative
Ask: E: A number whose absolute value is 0
A: A negative number whose absolute value is 6
D: A positive number whose absolute value is 7
G: A positive number whose absolute value is 3
I: A negative number whose absolute value is 4
0: A positive number whose absolute value is 5
P: A negative number whose absolute value is 10
R: A negative number whose absolute value is 8
S: A negative number whose absolute value is 2
Answer:
E. 0
A. –6
D. 7
G. 3
I. –4
O. 5
P. –10
R. –8
S. –2
Remember: The absolute value of a number means the distance from zero.
Step-by-step explanation:
hope it helps po. pwede po paki-brainliest. need lang po for the next rank. thank you po❤️
Find two integers1.) Whose sum is 13 and whose difference
Ask: Find two integers
1.) Whose sum is 13 and whose difference is 23.
2.) Whose sum is -7 and whose difference is 25.
3.) Whose sum is -23 and whose difference is 37.
Answer:
1.36
2.14,625
3.26,851
Step-by-step explanation:
Sana makatulong ito sa iyong pag-aaral❤
whose are the people whose work are related to environmental
Ask: whose are the people whose work are related to environmental health
DENR
Explanation:
Environmental Toxicologist
Air Pollution Analyst
Pa help itong tatlo nalang hindi ko pa nasasagutan.Find two
Ask: Pa help itong tatlo nalang hindi ko pa nasasagutan.
Find two integers
1.) Whose sum is 13 and whose difference is 23.
2.) Whose sum is -7 and whose difference is 25.
3.) Whose sum is -23 and whose difference is 37.
Answer:
1.16,299
2.14,350
3.46,1702
Step-by-step explanation:
Sana makatulong ito sa iyo
Hope it help
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